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100-a^2-6a-9=0
We add all the numbers together, and all the variables
-1a^2-6a+91=0
a = -1; b = -6; c = +91;
Δ = b2-4ac
Δ = -62-4·(-1)·91
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-20}{2*-1}=\frac{-14}{-2} =+7 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+20}{2*-1}=\frac{26}{-2} =-13 $
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